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12y^2-9y-64=0
a = 12; b = -9; c = -64;
Δ = b2-4ac
Δ = -92-4·12·(-64)
Δ = 3153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{3153}}{2*12}=\frac{9-\sqrt{3153}}{24} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{3153}}{2*12}=\frac{9+\sqrt{3153}}{24} $
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